AIcoding 第 5 步 todo 开发(开发计划 v2.0)前半段: - T-1 3 张新表 DDL(core_convert_request 6 态 ENUM / core_trade_calendar / core_share_rule)+ 种子 + sqlite 单一事实源同步 + 列清单断言 - T-2/T-2b calc 扩展(product_round/redeem_amount/partial_qty)+ 真实净值实算回填 - T-3 convert_request_repository(6 态 + 条件 UPDATE 守卫)+ core_ro 三读方法 + share_lot_repository.available_qty_with_inflight(R-3 在途占用推导) - T-4 convert_repository.sync_mirror 成为 risk_convert_detail 唯一进度镜像写入口 (旧三方法标 Deprecated,T-7 后删) - T-5 locks.py 锁键构造器 convert_req_lock_key / convert_confirm_lock_key - T-6 convert_service.accept_convert 受理事务(八步:锁→幂等→校验→受理日顺延 →在途占用校验→落单→镜像+审计→202;不扣份额/不折算/不写流水) + tests/test_convert_accept.py(16 用例) + scripts/dev/verify_convert_accept.py(真库 36/36 一致) + trading_calendar.py 纯函数包(R-5)+ 21 用例 T-6 真库实测暴露并修复:confirm_eta 在日历数据边界抛 ValueError,会让已落库 的受理单在调用方眼里变 500;改为展示性字段容错 + 单测守护。 基线:798 passed / 10 skipped,零回归。
175 lines
7.1 KiB
Python
175 lines
7.1 KiB
Python
# -*- coding: utf-8 -*-
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"""基金转换主示例实算(T-2b · PRD §5.3 数值来源 · 禁止手算)。
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**为什么必须调用生产 `app.service.convert.calc` 而不是脚本内再写一套公式**
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v0.7 曾两次因「手算与口径不符」被外部审查质疑;而"脚本自己实现一份公式"
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是同一类问题的变体——**两处公式必然漂移**(生产 `calc.py` 改了、脚本没改,
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PRD 里的数字就变成假证据)。这与 D18(批次补建规则只留一个副本)是同一条纪律。
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故本脚本:
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1. **只做输入准备与输出打印**,全部计算走 `calc` / `fee` 的生产函数;
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2. 打印后与 PRD §5.3 的**期望值逐项比对**,不一致即 `exit 1`
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—— 这样它同时是一道「PRD 数字 ↔ 生产口径」一致性门禁。
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运行:<托管 Python> scripts/dev/calc_convert_demo.py
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"""
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from __future__ import annotations
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import sys
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from datetime import date, datetime, time, timedelta
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from decimal import Decimal
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from pathlib import Path
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# ① sys.path 引导项目根(直跑脚本时 sys.path[0] 为脚本目录;同 verify_convert_seed 先例)
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ROOT = Path(__file__).resolve().parents[2]
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sys.path.insert(0, str(ROOT))
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from app.service.convert import calc, fee # noqa: E402
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from app.service.convert.types import FeeRule, Lot # noqa: E402
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#: 与 PRD §5.3 同一交易日(也是 06-seed-nav.sql 的净值日期)。
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TRADE_DATE = date(2026, 9, 9)
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#: 07-seed-fee-rule.sql 的赎回费五档(22 号文 §10 下限)。
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RULES = [
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FeeRule(0, 7, Decimal("0.0150")),
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FeeRule(7, 30, Decimal("0.0100")),
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FeeRule(30, 180, Decimal("0.0050")),
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FeeRule(180, 365, Decimal("0.0025")),
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FeeRule(365, None, Decimal("0.0000")),
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]
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# 两端同属**华夏模拟基金 / TA-CN-001**(满足转换前置硬约束:同管理人 + 同 TA)。
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# T-2b:净值取 06-seed-nav.sql 在 T=2026-09-09 的**真实净值**(PRD §5.3.2 声明来源,
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# 禁止用虚构值——验收 20「示例与种子强绑定」)。
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NAV_OUT = Decimal("1.3604") # PROD-110022 稳健债基 A(bond)@2026-09-09
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NAV_IN = Decimal("1.9194") # PROD-003095 医药健康精选(stock / 主动偏股型)@2026-09-09
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SUB_RATE_OUT = Decimal("0.0030") # 转出端申购费率(债基,22 号文 §8 上限 0.3%)
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SUB_RATE_IN = Decimal("0.0080") # 转入端申购费率(主动偏股型,上限 0.8%)
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REQUESTED_QTY = Decimal("50000.0000")
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#: PRD §5.3 期望值 —— 实算结果必须逐项命中(T-2b 由生产 calc 实算回填,禁手算)。
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EXPECTED = {
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"批次 1 amount": "40812.00",
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"批次 1 fee": "204.06",
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"批次 2 amount": "27208.00",
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"批次 2 fee": "408.12",
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"out_amount": "68020.00",
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"redeem_fee": "612.18",
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"convert_amount": "67407.82",
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"diff_fee(B)": "333.36",
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"in_amount": "67074.46",
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"in_qty(B)": "34945.54",
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"rounding_diff": "-0.0049",
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"diff_fee(A)": "335.36",
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"in_qty(A)": "34944.49",
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"同费率 diff_fee": "0.00",
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"同费率 in_qty": "35119.21",
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}
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def _lot(lot_id: str, hold_days: int, qty: str, nav: Decimal) -> Lot:
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"""构造 `hold_days` 天前确认的批次(交易日固定为 TRADE_DATE)。"""
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confirmed = datetime.combine(TRADE_DATE - timedelta(days=hold_days), time(10, 0, 0))
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return Lot(
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lot_id=lot_id,
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confirmed_at=confirmed,
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remain_qty=Decimal(qty),
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nav=nav,
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qty=Decimal(qty),
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)
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def compute() -> dict[str, str]:
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"""跑一遍主示例全链,返回**结果字典**(键与 EXPECTED 对齐)。"""
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# —— 输入:跨 2 个批次、持有期不同 → 费率不同(30000 份满 30 日 / 20000 份不足 7 日)
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lots = [
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_lot("LOT-DEMO-01", 100, "30000.0000", NAV_OUT),
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_lot("LOT-DEMO-02", 3, "20000.0000", NAV_OUT),
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]
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plan = calc.plan_lots(lots, REQUESTED_QTY)
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result: dict[str, str] = {}
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# —— 逐批:先各自 2 位舍入、再求和(PRD §12「舍入顺序」)——
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out_amount = Decimal("0")
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redeem_fee = Decimal("0")
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for idx, alloc in enumerate(plan.allocations, start=1):
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hold_days = calc.hold_days(TRADE_DATE, alloc.confirmed_at)
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rate = fee.pick_fee_rate(RULES, hold_days)
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amount = calc.lot_amount(alloc.qty, alloc.nav)
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fee_amount = calc.lot_fee(amount, rate)
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out_amount += amount
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redeem_fee += fee_amount
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result[f"批次 {idx} amount"] = str(amount)
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result[f"批次 {idx} fee"] = str(fee_amount)
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print(
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f"批次 {idx}({alloc.lot_id}){alloc.qty} 份 / 持有 {hold_days} 天 / "
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f"费率 {rate}({rate * 100}%)→ amount={amount} fee={fee_amount}"
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)
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convert_amount = calc.convert_amount(out_amount, redeem_fee)
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result["out_amount"] = str(out_amount)
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result["redeem_fee"] = str(redeem_fee)
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result["convert_amount"] = str(convert_amount)
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# —— 口径 B:价外法两端差(本期默认,PRD §2.1.1)——
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diff_b = calc.diff_fee(convert_amount, SUB_RATE_OUT, SUB_RATE_IN, "amount_diff")
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in_amount = calc.convert_amount(convert_amount, diff_b)
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in_qty_b = calc.in_qty(in_amount, NAV_IN)
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result["diff_fee(B)"] = str(diff_b)
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result["in_amount"] = str(in_amount)
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result["in_qty(B)"] = str(in_qty_b)
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result["rounding_diff"] = str(calc.rounding_diff(in_amount, NAV_IN, in_qty_b))
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# —— 口径 A:费率差法(配置 convert_diff_fee_mode='rate_diff' 时启用)——
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diff_a = calc.diff_fee(convert_amount, SUB_RATE_OUT, SUB_RATE_IN, "rate_diff")
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in_qty_a = calc.in_qty(calc.convert_amount(convert_amount, diff_a), NAV_IN)
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result["diff_fee(A)"] = str(diff_a)
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result["in_qty(A)"] = str(in_qty_a)
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# —— 同费率对照(两端均为 0.0030)→ 补差 0,用于 PRD §9 第 19 条 ——
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diff_same = calc.diff_fee(convert_amount, SUB_RATE_OUT, SUB_RATE_OUT, "amount_diff")
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in_amount_same = calc.convert_amount(convert_amount, diff_same)
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result["同费率 diff_fee"] = str(diff_same)
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result["同费率 in_qty"] = str(calc.in_qty(in_amount_same, NAV_IN))
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return result
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def main() -> int:
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print("=== 主示例实算(与生产 calc.py 同一套公式)===")
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actual = compute()
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print()
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print("=== 与 PRD §5.3 期望值逐项比对 ===")
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mismatches = []
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for key, expected in EXPECTED.items():
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got = actual.get(key, "<缺失>")
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ok = got == expected
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if not ok:
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mismatches.append((key, expected, got))
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print(f" [{'OK ' if ok else 'FAIL'}] {key:<18} 期望 {expected:<12} 实算 {got}")
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if mismatches:
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print()
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print(f"❌ {len(mismatches)} 项不一致 —— PRD 数字或生产口径已被改动,停下查清:")
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for key, expected, got in mismatches:
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print(f" · {key}:期望 {expected} / 实算 {got}")
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return 1
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print()
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print(f"✅ 全部 {len(EXPECTED)} 项与 PRD §5.3 一致(口径 B in_qty=34945.54)")
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return 0
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if __name__ == "__main__":
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try: # Windows 控制台默认 cp936,避免打印中文报错
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sys.stdout.reconfigure(encoding="utf-8")
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except Exception: # noqa: BLE001 - 环境不支持时忽略,不影响计算
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pass
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raise SystemExit(main())
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